Posts for Erockbrox1

Experienced Forum User
Joined: 1/3/2011
Posts: 6
Mr. Pwnage wrote:
No, it's based on whether the timer is even or odd. See, Eggman runs his plant on 0.5Hz AC hydroelectricity!
Thanks. You are correct!
Experienced Forum User
Joined: 1/3/2011
Posts: 6
I have been playing Sonic 2 for years. I grew up with the game as a kid but recently I've been trying to figure out how in the heck the pipes work in the Chemical Plant Zones. There are many places where a single entrance to a pipe will split into two different paths and what I need to know is how the game decides what path Sonic will take. Is this a random element or can the player control what path Sonic will take once he goes into the pipe? Anyone know or have an idea. Thanks. I just figured it out. But yes you are correct its the time even or odd.
Experienced Forum User
Joined: 1/3/2011
Posts: 6
This thread can be closed. Everything has been solved. We now know for a fact that you cannot hit both bandits with a single trap. The $10.00 was going to be given if you could hit them both.
Experienced Forum User
Joined: 1/3/2011
Posts: 6
P.JBoy wrote:
You can not hit two of them at the same time, just use an invincibility cheat (set $0038 to 00) and wait for them to come to where you are and use it, it only works on one of them. Here, download this less-than-one-megabyte AVI
Thank you so much for your help. I watched the video. Indeed if you just stand there both bandits will go to you and have the same exact position. When you set the trap only one gets hit. So proves that it cannot be done. Thank you again. This is what I really wanted to see. If it was even possible in the first place. Now I know that it is not.
Experienced Forum User
Joined: 1/3/2011
Posts: 6
The run must be a video posted on youtube and all of the 30 traps must be seen being hit by both bandits on screen. Each trap must be a double hit. No off screen hits because you can’t see that happening. Keep in mind that some traps can be used more than once. But every time they are used it must be a double hit on both bandits. 29 traps was a misprint. It really is 30.
Post subject: Need TASer for Perfect Home Alone Score NES
Experienced Forum User
Joined: 1/3/2011
Posts: 6
Hi, I never posted in these forums here but I am here because I need a TASer. There has been much debate on the Twin Galaxies (official score keepers of video games) message boards regarding a perfect score on Home Alone NES. http://forums.twingalaxies.com/viewtopic.php?f=49&t=24714 http://forums.twingalaxies.com/viewtopic.php?f=49&t=24647 To hopefully put an end to all this debate I will be willing to pay a TASer by paypal to anyone who can post a youtube video of world’s first perfect Home Alone score. This score will be the absolutely theoretically highest possible score that can be produced pulling out all the stops using TAS. The amount that I will be paypaling is $10.00 USD. I know it may not much but I know time and effort is put into these runs. So I’m trying to compensate for that. What must be done in the video to produce a perfect score? There are 30 traps in the entire game. In a normal game if you use all of the traps the highest score is 141,280 points but there had been lots of talk that it is possible to hit both bandits with a single trap if it’s done on the same frame. That means that both bandits would have to be hit by all 30 traps, resulting with a grand total of 270,560 points. There is also a screen when you complete the game which shows the bandits being captured by a police man right before you see the final score. This screen must be manually passed by pressing enter before 1 second has elapsed. It turns out that this screen gives you 10 points per second and those points should not be counted. Among the 30 traps there are 4 chandeliers which must be dropped down from the ceiling. The best way from what I’ve heard to make them hit both bandits is to let the bandits run into them in midair by the chandelier hitting them at the chest level. Now I’ve never been able to hit both bandits with a single trap which apparently can only be accomplished if they both hit the same trap at the same time on the same frame knocking them both out. Someone would have to verify that this is possible by confirming that it is possible to hit both bandits with a single trap. If you have any questions or are interested in regarding this bounty feel free to ask me.